Chemistry, asked by mitalirathore398, 1 year ago

The smallest ketone and its next homologue are reacted with NH₂OH to form oxime (a) Two different oximes are formed(b) Three different oximes are formed(c) Two oximes formed are optically active(d) All oximes formed are optically active

Answers

Answered by Sweetbuddy
0

Hey buddy here is ur answer !!

The smallest ketone and its next homologue are reacted with NH₂OH to form oxime .

So its products are (CH3)2C = NOH product of its homolgue is CH3CH2C(CH3) = NOH .

》BE BRAINLY 《

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