First Find base and height, and then the area of the given parallelogram with all steps
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ABCD is the parallelogram. AC is the daigonal which divides the parallelogram into 2 equal parts.
so in triangle ADC, AC if base = 8 cm and height is 3 cm.
so it's area is = 1/2base * height
=1/2*8*3
=12cm sq.
area of parallelogram= 12 ×2 = 24 cm sq.
base= 8 cm [given]
height-
area=1/2 bh
→12= 1/2×5×h
→h=24×2/5
→h= 9.6 cm
hope u get the answer
so in triangle ADC, AC if base = 8 cm and height is 3 cm.
so it's area is = 1/2base * height
=1/2*8*3
=12cm sq.
area of parallelogram= 12 ×2 = 24 cm sq.
base= 8 cm [given]
height-
area=1/2 bh
→12= 1/2×5×h
→h=24×2/5
→h= 9.6 cm
hope u get the answer
Anchaljain06:
Here it is written first find base and height.
Thank You
Answer is Correct, but we had to find height of parallelogram and not of Triangle. But, no Problem Rest I can Solve myself
ur welcome happy to help you
:-D
Answered by
0
Answer:
Step-by-step explanation:
Base Is already given
Height is already given
Area of triangle ADC=1/2*3*8=12
PC is diagonal and diagonal divide the program into two Triangles of equal area
area ll ABCD=2*ar∆ADC
=2*12
=24
Thank You
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