The smallest no. that must be subtracted from 2800 so that the obtained no.
is a perfect square
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Answered by
2
you must subtract 96so it will become 2704
which is square of52
hope it help you
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which is square of52
hope it help you
please mark me brainlist
Answered by
1
First of all find the closest perfect square on both the limits of 2800 that we have = 2500; 2601; 2704; 2809;
We can clearly see that 2809 is greater than 2800 and thus we have to subtract something so we'll choose 2704 as closest.
Therefore, the smallest no. that must be subtracted from 2800 so that, obtained number is a perfect square = 96
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