Math, asked by Mehardeep, 1 year ago

The smallest number by which 1188 must be divided to obtain a perfect cube

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Answers

Answered by ExoticExplorer
58
No, 1188 isn't a perfect cube. 
1188=2×2×3×3×3×11... to make it perfect cube we should remove 2×2×11 mrans44.
44 is the smallest natural no. so that quotient will become perfect cube.

Hope This helps :)
Answered by qwsuccess
1

Given: A number 1188

To find: The smallest number by which 1188 must be divided to obtain a perfect cube

Solution: Using prime factorization, the given number can be expressed as:

1188 = 2 × 2 × 3 × 3 × 3 × 11

Since 2 × 2 and 11 are left after grouping in triplets, to make 1188 a perfect cube, we should divide it by 2 × 2 × 11 i.e., 44, then the prime factorization of quotient will not contain 2 × 2 and 11.

∵ 1188 ÷ 44 = 27  (3 × 3 × 3), which is a perfect cube.

Hence, the smallest number by which 1188 must be divided to obtain a perfect cube is 44.

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