The smallest number by which 1188 must be divided to obtain a perfect cube
If someone got the answer of this question ,he/ she love maths
Answers
Answered by
58
No, 1188 isn't a perfect cube.
1188=2×2×3×3×3×11... to make it perfect cube we should remove 2×2×11 mrans44.
44 is the smallest natural no. so that quotient will become perfect cube.
Hope This helps :)
1188=2×2×3×3×3×11... to make it perfect cube we should remove 2×2×11 mrans44.
44 is the smallest natural no. so that quotient will become perfect cube.
Hope This helps :)
Answered by
1
Given: A number 1188
To find: The smallest number by which 1188 must be divided to obtain a perfect cube
Solution: Using prime factorization, the given number can be expressed as:
1188 = 2 × 2 × 3 × 3 × 3 × 11
Since 2 × 2 and 11 are left after grouping in triplets, to make 1188 a perfect cube, we should divide it by 2 × 2 × 11 i.e., 44, then the prime factorization of quotient will not contain 2 × 2 and 11.
∵ 1188 ÷ 44 = 27 (3 × 3 × 3), which is a perfect cube.
Hence, the smallest number by which 1188 must be divided to obtain a perfect cube is 44.
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