Question

The smallest number divisible by the sum of first 10 whole numbers

Answer 1

Hello Dear!!!

Here's your answer...

The sum of first 10 whole numbers is

one number is 0

so...dont count 1 number..

Sum of first 9 numbers is 

n(n+1)/2

9*10/2

90/2

45

45 is divisible by 3

The smallest number which divides 45 is 3

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HOPE THIS HELPS YOU...

Answer 2

Hello dear user!!! ✌️✌️



Here is your answer goes like this:

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QUESTION :





ANSWER:

GIVEN;

The sum of first 10 whole numbers are :

one number is 0, we get

Dont count 1 number..

Sum of first 9 numbers is

=>n(n+1)/2

=>9*10/2

=>90/2

=>45

HENCE 45 IS DIVISIBLE BY 3......

the smallest number that divides 45 is 3

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I HOPE THIS WILL HELPS YOU ✌️✌️




HAVE A GREAT DAY AHEAD ✌️✌️



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