The smallest number of 4 digits exactly divisible by 12, 15, 18 and 27 is
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17
Answer:
1539.851 is exactly divisible by 12, 15, 18 , 27
Step-by-step explanation:
first find the LCM of 12, 15, 18, and 27
= 540
smallest 4 - digit no = 1000
divide 1000 by 540
remainder = 1.851
req. no. = 1000+(540-1.851)
= 1000+539.851
=1539.851
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