Question

The smallest number which when divided by 17, 23 and 29 leaves a remainder 11 in each case is:

(a) 493 (b) 11350
(c) 11339 (d) 667​

Answer 1

Answer:

(b)11350

Step-by-step explanation:

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Answer 2

Answer:

The smallest number is 11350.

Step-by-step explanation:

Taking lcm of 17,23 and 29, we get,

Lcm of 17,23 and 29 = $17\times 23\times 29$ = 11339

To leave a remainder of 11 when the required number is divided by 17 or 23 or 29, we have to add 11 to the lcm of 17,23 and 29

∴

11339 + 11 = 11350

The correct answer is option (b) 11350.