The smallest number which when divided by 4 6 or 7 leaves a remainder of 2 is
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I first find the smallest possible number which is divisible by 4,6 and 7. With a prime factorization you can easily find that this number is 84. Therefore, 86 (84+2) will be the smallest possible number which when divided by 4, 6 or 7 leaves a remainder of 2. Hence answer should be D.
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I prefer attachment for solution..❣️..
Answer is 86✌️
HOPE SO IT IS HELPFUL..♥️..
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