Question

The smallest number which when increased by
2 is divisible by each one of 36, 45 and 50. is
(a) 900 (b) 898 (c) 902 (d) 452​

Answer 1

Answer:

468 when increased by 17, can be found out by LCM method

$$\begin{lgathered}\begin{array}{l}{520=2 \times 2 \times 2 \times 5 \times 13} \\ {468=2 \times 2 \times 3 \times 3 \times 13}\end{array}\end{lgathered}$$

LCM of 520 and 468 = $$2 \times 2 \times 2 \times 3 \times 3 \times 5 \times 13=4680$$

Now the total value that is to be divided or the smallest number after increase by 17 becomes 4680, therefore the smallest number will be,

4680 – 17 = 4663

Therefore the number after subtraction of 17 becomes 4663

hope it's helpful

please make as brainlist

thank you