Math, asked by radhey24, 1 year ago

the smallest positive integer divisible by all the integer from 2 to 10 is......

Answers

Answered by hitesh3567
15
1 = 1
2 = 2
3 = 3
4 = 2*2
5 = 5
6 = 2*3
7 = 7
8 = 2*2*2
9 = 3*3
10 = 2*5
The LCM of all of these will be the product of all the different factors. When a factor appears in more than one list of factors, use the longest string of this factor. So:
LCM = 1*2*2*2*3*3*5*7 = 2520
(The factors 2 and 3 appeared in more than one list of factors. So we use the longest string of each. We used the string of 3 2's from the list of factors for 8 and the string of 2 3's from the list of factors for 9.)

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