The solid cylinder has TSA of 462 cm square its CSA is one third of its surface area find the volume of cylinder.
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Answered by
2
TSA =462
2πr(h+r)=462
rh+r^2=462*7/22*2
rh+r^2=147/2. ---------------(I)
now,
CSA=1/3TSA
2πrh=154
rh=154*7/22*2
rh=49/2----------(II)
Now on putting rh =49/2 in 1st equation, we get
49/2+r^2=147/2
r^2=147/2-49/2
r^2= 98/2
r^2=49
r=7.
now putting r=7 in II equation, we get
7*h=49/2
h=7/2.
if my answer is helpful for you then please mark as brain liest
2πr(h+r)=462
rh+r^2=462*7/22*2
rh+r^2=147/2. ---------------(I)
now,
CSA=1/3TSA
2πrh=154
rh=154*7/22*2
rh=49/2----------(II)
Now on putting rh =49/2 in 1st equation, we get
49/2+r^2=147/2
r^2=147/2-49/2
r^2= 98/2
r^2=49
r=7.
now putting r=7 in II equation, we get
7*h=49/2
h=7/2.
if my answer is helpful for you then please mark as brain liest
Answered by
7
TSA of cylinder = 462 sq cm
2πrh+2πr^2=462
2πr(h+r) =462 ...... (1)
also,
CSA of cylinder(2πrh)=1/3*462
⇒2πrh=154 ....... (2)
From equation (1)÷(2)
r+h/h = 462/154 =3
r+h = 3h
2h = r
h = r/2
We have,
2πrh = 154
2×22/7×r×r/2 =154
r = 7 cm
h = r/ 2 = 3.5 cm
Volume of cylinder =πr^2h
= 22/7× 7 ×7 × 3.5
= 539 cm^3
Hope it helps :)
2πrh+2πr^2=462
2πr(h+r) =462 ...... (1)
also,
CSA of cylinder(2πrh)=1/3*462
⇒2πrh=154 ....... (2)
From equation (1)÷(2)
r+h/h = 462/154 =3
r+h = 3h
2h = r
h = r/2
We have,
2πrh = 154
2×22/7×r×r/2 =154
r = 7 cm
h = r/ 2 = 3.5 cm
Volume of cylinder =πr^2h
= 22/7× 7 ×7 × 3.5
= 539 cm^3
Hope it helps :)
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