Question

the solubility in water of a sparingly soluble salt MN2 is 4.0×10power -4 mol /L it's solubility product number will be​

Answer 1

we have to find the solubility product number of sparingly soluble salt MN₂. solubility of salt in water is 4 × 10¯⁴ mol/L.

solution : MN₂ ⇔M²⁺ + 2N¯

s 2s

so, solubility product , Ksp = [M²⁺]¹[N¯]²

= (s)(2s)²

= 4s³

= 4(4 ×10¯⁴)³

= 256 × 10¯¹²

= 2.56 × 10¯¹⁰

Therefore the solubility product of salt is 2.56 × 10¯¹⁰ mol³/L³

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Answer 2

Answer:

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