Question

The solubility of a solute 'X' in water is 35 g in 100 g of water. The density of the solution is 1.5 ml^-1. The concentration of 'X' in the solution in % (m/v)
is:
(A) 60%
(B) 38.88%
(C) 34%
(D) 88%​

Answer 1

Answer:

B) 38.88 %

Here is your answer

Answer 2

In the solution which is formed,

$\frac{mass}{volume} = density$

$\frac{100 + 35}{v} = 1.5$

$\frac{135}{v} = 1.5$

$1.5v = 135$

$v = \frac{135}{1.5} = 90$

therefore volume of solution = 90

therefore,

Concentration of X in solution =

=

$\frac{mass \: of \: x}{vol \: of \: solution} \times 100$

$\frac{35}{90} \times 100$

38.88%