Chemistry, asked by sadiyasiddique94, 3 months ago

The solubility of AgCl in 0.1 M aqueous NaCl solution
is (Ksp of AgCl = 1.8 x 10-1)
1.8 x 10-3
1.8 x 10-11
0.9 x 10-3
1.8 x 10-9

Answers

Answered by junaid609khan

0

Answer:

1.8 x 10-3=15. 1.8x10-11=7. 0.9x10-3=6. 1.8x10-9=9

Explanation:

(ksp of agcl =1.8x10-1=17 hope it's help you

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