Question

The solubility of agcl in a 0.1 m kcl solution will be

Answer 1

Hi,

I think this question is missing the value of ksp

But if this is so, then the value of ksp is 1.8 x 10^-10. And therefore the question should be phrased as follows;

Calculate the solubility of AgCl (Ksp = 1.8 x10-10) in 0.1 M, KCl

So we can calculate it as follows;

AgCl ---------> Ag+ + Cl-

ksp = S²

S = √1.8 x10-10

S = 1.34 x 10^-5

So the solubility in 0.1 M KCl

determine the new ksp = 1.34 x 10^-5 x (0.1) = 1.34 x 10^-6

So the new solubility is = √1.34 x 10^-6

= 1.16 x 10^-3 M