Chemistry, asked by architamk02, 7 months ago

The solubility of AgCl is m g dm^-3.If 1 mole of AgCl weighs M g the solubility product of AgCl will be A) m^2/M B) m/M^2 C) m^2/M^2 D) m^2M^2

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Answered by brainlyboy1248
3

Iᴛ sᴇᴇᴍᴇᴅ ᴛʜᴀᴛ ʙʀᴀɪɴʟʏ ᴍᴏᴅᴇʀᴀᴛᴏʀs ᴅᴏᴇsɴᴏᴛ ʟɪᴋᴇ ᴍʏ ᴀɴsᴡᴇʀ sᴏ ᴛʜᴀᴛ ɪ ʜᴀᴅ ᴛᴏ ᴛᴀᴋᴇ sᴄʀᴇᴇɴsʜᴏᴛ ᴏғ ɪᴛ

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