Question

The solubility of common salt at 30 C is 36g Calculate the amount of water required to prepare a saturated solution of 9g of salt at the given temperature

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Answer 1

Answer :-

Given :

• The solubility of common salt (NaCl) at 30°C is 36 g.

To find :

• Amount of water required to prepare a saturated solution of 9 g at the given temperature.

Solution :

We have:

⇒ Weight of NaCl = 9 g

⇒ Solubility of NaCl = 36 g

We know:

⇒ Solubility of solute:

• Weight of solute/Weight of solvent × 100

Hence:

⇒ 36 = 9/x × 100

⇒ 36 = 900/x

⇒ 36x = 900

⇒ x = 900/36

∴ x = 25

∴,

The amount of water required to prepare the saturated solution is 25 g.

Answer 2

Answer:

weight of salt = 90 gram,

solubility = 50

by using sing formula:

solubility of solute =

90gm/50 ×100

180gm Ans.