Question

The solubility of is x mole/lit. Then its solubility product is . A is.

Answer 1

Answer:

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Answer 2

Ag2CrO4(s)⇔2Ag++CrO42−

Ag2CrO4(s)⇔2Ag++CrO42−                               2S            S

Ag2CrO4(s)⇔2Ag++CrO42−                               2S            SKsp=[Ag+]2×[CrO42−]

Ag2CrO4(s)⇔2Ag++CrO42−                               2S            SKsp=[Ag+]2×[CrO42−]Ksp=(2S)2×S=4S3

Ag2CrO4(s)⇔2Ag++CrO42−                               2S            SKsp=[Ag+]2×[CrO42−]Ksp=(2S)2×S=4S3Hence, option C is correct.