Question

The solubility of sb2s3 in water is 1*10^-5 ksp is

Answer 1

Heyaa!

Answer:Ksp=[A+3][ X2-]3 = 1.1 x 10-23.

Hence,

The solubility of sb2s3 in water is 1*10^-5 ksp is = [A+3][ X2-]3 = 1.1 x 10- 23.

ThaNks!!☺️✌

Answer 2

The solubility of antimony trisulfide is 0.039 M

Explanation:

Solubility product is defined as the product of concentration of ions present in a solution each raised to the power its stoichiometric ratio.

The equation for the ionization of the antimony trisulfide is given as:

       $Sb_2S_3\leftrightharpoons 2Sb^{3+}+3S^{2-}$

                       2s       3s

Expression for the solubility product of $Sb_2S_3$ will be:

$K_{sp}=[Sb^{3+}]^2[S^{2-}]^3\\\\K_{sp}=(2s)^2\times (3s)^3=108s^5$

We are given:

$K_{sp}=1\times 10^{-5}$

Putting values in above equation, we get:

$1.0\times 10^{-5}=108s^5\\\\s=0.039M$

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