Chemistry, asked by ranevasundhara12345, 1 year ago

The solubility of silver chloride is 1.5 * 10^-3 g/dm^3 calculate solubility product

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Answered by SunnyG07

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Answered by realmess

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Ksp= Ag+ + Cl-

$ksp = s ^{2}$

ksp = (1.5 * 10^-3 ) square

ksp= 2.25*10^-6

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