The solubility of substance X at 25°C and 50°C are 35 and 50. If 300g of saturated solution at 50°C is cooled to 25°C. Determine max mass of X separated out in grams.
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Answer:
weight of salt = 90 gram,
solubility = 50
sing formula
solubility of solute =
weightofsolventinsaturatedsolution
weightofsoluteinsaturatedsolution
×100
or 50=
weightofsolventinsaturatedsolutio
90gm
×100
so weight of solvent in saturated solution =
50
90gm
×100=180gm
Hence 180 gm of water is required to prepare a saturated solution.
Explanation:
hope it will help you .........
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