The solubility product of ferric hydroxide is 1.1×10^-36 M1.1×10−36M at 25°C. calculate the solubility of ferric hydroxide in gram/litre.gram/litre.
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Answer:
Fe(OH)3=Fe3++3OH⊝
∴[Fe3+][OH−]3=Ksp of Fe(OH)3=1×10−36
⇒[OH⊝]3=0.0011×10−36
⇒[OH⊝]=(10−33)Y3=10−11M
∴ The minimum concentration of OH⊝ will be 10−11M .
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