Question

The solubility product of Mg(OH)2 is 10^-14. The molar solubility of Mg(OH)2 in a buffer solution of ph =8 is​

Answer 1

Answer:

Mg(OH)

2

⇌Mg

2+

+2OH

−

S 2S

K

sp

=[Mg

2+

][OH

−

]

2

=(S)(2S)

2

=4S

3

=5×10

−19

So S=5×10

−7

means [OH

−

]=2S=10

−6

So pOH=−log([OH

−

])=6

As we know pH+pOH=14

So pH=8