The solubility product of MOH is 1x10-10Mºther solution will be: 1) 10 2) 9 3) 4
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Answer:
Solubility product of MOH is 10
−10
mol
2
dm
−2
.
K
sp
=10
−10
mol
2
dm
−2
MOH⇌M
+
+OH
−
K
sp
(M(OH)
2
)=10
−10
=S
2
S=10
−5
⇒[OH
−
]=10
−5
pOH=5(∵pOH=−log[OH
−
])
pH=9(∵pH=14−pOH)
∴ pH of aqeous solution is 9.
Explanation:
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