The solution having minimum boiling point is
(1) 0.1 M C6H1206
(3) 0.1 M NaCl
(2) 0.1 M CaCl2
(4) 0.5 M AICI3
Answers
Answer:
I will tell you the easiest way to solve this question.
First of all, remember the equation for elevation of boiling point.
∆T = i* Kb * M, where "i" is the vant Hoff factor, Kb is the elevation constant and M is the molality.
Now for aqueous solution , Kb is a constant.
In that case, when the (i*M) is lowest, the boiling point will be lowest.
Calculate the vant Hoff factor for all the four options,
in option
a) i= 1
b) i= 2
c) i= 3
d) i= 4
Now calculate (i* M)
so in option
a) the value is 1* 0.1 =0.1
b) the value is 2* 0.1 = 0.2
c) the value is 3* 0.1 = 0.3
d) the value is 4* 0.5 = 2
SINCE IN OPTION A) THE VALUE OF (i*M) IS MINIMUM, THAT SOLUTION WILL HAVE LEAST BOILING POINT.
SINCE IN OPTION A) THE VALUE OF (i*M) IS MINIMUM, THAT SOLUTION WILL HAVE LEAST BOILING POINT.
Explanation:
this will definitely help you