Question

The solution having minimum boiling point is
(1) 0.1 M C6H1206
(3) 0.1 M NaCl
(2) 0.1 M CaCl2
(4) 0.5 M AICI3
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Answer 1

Answer:

I will tell you the easiest way to solve this question.

First of all, remember the equation for elevation of boiling point.

∆T = i* Kb * M, where "i" is the vant Hoff factor, Kb is the elevation constant and M is the molality.

Now for aqueous solution , Kb is a constant.

In that case, when the (i*M) is lowest, the boiling point will be lowest.

Calculate the vant Hoff factor for all the four options,

in option

a) i= 1

b) i= 2

c) i= 3

d) i= 4

Now calculate (i* M)

so in option

a) the value is 1* 0.1 =0.1

b) the value is 2* 0.1 = 0.2

c) the value is 3* 0.1 = 0.3

d) the value is 4* 0.5 = 2

SINCE IN OPTION A) THE VALUE OF (i*M) IS MINIMUM, THAT SOLUTION WILL HAVE LEAST BOILING POINT.

SINCE IN OPTION A) THE VALUE OF (i*M) IS MINIMUM, THAT SOLUTION WILL HAVE LEAST BOILING POINT.

Answer 2

Explanation:

this will definitely help you