Question

the solution of 15<3(x-2)/5<0​

Answer 1

⠀⠀⠀⠀⠀⠀$\huge\underbrace\mathcal\pink{Solution}$

$15< \frac{3(x - 2)}{5} < 0 \\ multiplying \: the \: eqn \: with \: 5 \\15 \times 5< \frac{3(x - 2)}{5} \times 5< 0 \times 5 \\ 75 < 3(x - 2) < 0 \\dividing \: the \: eqn \: with \: 3 \\ \frac{75}{3} < \frac{3(x - 2)}{3} < \frac{0}{3} \\ 25 < x - 2 < 0 \\ adding \: the \: eqn \: with \: 2 \\ 25 + 2 < x - 2 + 2 < 0 + 2 \\ 27 < x < 2$

This means x is greater than 27 but less than 2.

Conclusion---

There is no any number greater than 27 and less than 2.

So, x ∈ ϕ

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