Question

the solution of equation 3x-2y=4 and 2x-3y=1​

Answer 1

Solution

Given :-

• 3x - 2y = 4 --------(1)
• 2x - 3y = 1 -------(2)

Find :-

• Value of x & y

Explanation

Multiply by 3 in equ(2) & 2 in equ(1)

• 6x - 4y = 8
• 6x - 9y = 3

______________Sub . it's

==> -4y + 9y = 8 - 3

==> 5y = 5

==> y = 5/5

==> y = 1

Keep Value of y in equ(1)

==> 3x - 2 * 1 = 4

==> 3x = 4 + 2

==> 3x = 6

==> x = 6/3

==> x = 2

____________________

Hence

• Value of x = 2
• Value of y = 1

__________________

Answer 2

◇ Question ◇

→† the solution of equation 3x-2y=4 and 2x-3y

★ Given ★

→3x-2y=4

→2x-3y=1

$\rule{300}2$

○ Solution ○

multiply by 3 in eq(2) and 2 in eq(1)

$\leadsto 6x-4y=8$

$\leadsto 6x-9y=3$

$\leadsto 5y=8-3\\ \leadsto 5y=5\\ \leadsto y=1$

putting the value of y=1 in eq (1)

$\leadsto 3x-2y=4\\ \leadsto 3x-2×1=4\\ \leadsto 3x-2=4\\ \leadsto 3x=4+2\\ \leadsto 3x=6 \\ \leadsto x=3/6\\ \leadsto x=2$

★ HENCE,

→X=2

→Y=1

$\rule{300}2$