The solution of loh base x ( log base 2 ( log base2 x ) =0 is ??? Can anyone say this answer
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Remember that logarithms are exponents, and, consequently, the given logarithm "log₂ x" says to what power must I raise 2 in order to get x? ANSWER: 2 since it's given that log₂ x = 2; therefore, if we write the equivalent exponential statement to the given logarithm, we get:
2² = x
x = (2)(2); therefore, ...
x = 4
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