Math, asked by nikki8105, 1 year ago

The solution of the differential equation cosx cosy dx + sinx siny dy = cos2y dx, is

Answers

Answered by Anonymous
3
☆☆ranshsangwan☆☆

cosx cos y dy+sinx siny dx=0cosx cos y dydx+sinxsiny =0cosysinydydx+sinxcosx=0cotydy+tanxdx=0Integrating both sides we hav∫cotydy+∫tanxdx=∫0⇒log(siny)−log(cosx)=logC⇒logsinycosx=logC⇒sinycosx=C⇒siny=C cosx


Answered by Aditijani1
1
Nikki bhai sorry mujhe ye answer nahi aata hai
Similar questions