Question

The sum of three consecutive natural numbers divisible by 3 is 45. find smallest number

Answer 1

Hey sup!

Let the three consecutive numbers divisible by 3 be x ,x+3 and x+6 respectively.

So, x+x+3+x+6=45.
=> 3x+9=45.
=> 3x=45-9 = 36.
=> x=36/3 = 12.

So the numbers are 12,15 and 18.

Smallest number is 12 obviously.

Hope it helps.