Question

The solution of the differential equation dy/dx = y cot x is?

A) log(y) = log (sin x) + c
B) log(y) = log (cos x) + c
C) y = log (sin x) + c
D) y = log ( cos x ) + c​

Answer 1

Answer:

dy/dx + y cot x = cosec x,

Step-by-step explanation:

dy/dx + y cot x = cosec x, The above equation is of the form dydx+Py=Q d y d x + P y = Q i.e. linear differential equation.