Question

the solution of the pair of linear equations 4x - 3y= 8 and 6x-y =29/3 is ​

Answer 1

The values of x and y are: X=3/2and y=-2/3

Answer 2

$4x - 3y = 8 (eq \: 1)\\ 6x - y = \frac{29}{3} (eq \: 2) \\ eq \: 2 = > y = \frac{29}{3} - 6x \\ = > \frac{29 - 18x}{3}(eq \: 3) \\ \\ substituting \: eq \: 3 \: in \: eq \: 1 = > 4x - 3( \frac{29 - 18x}{3} ) \\ \\ 4x - 29 + 18x = 8 \\ 22x = 8 + 29 \\ x = \frac{37}{22} \\ subsituting \: x \: value \: in \: eq1 \\ 4( \frac{37}{22} ) - 3y = 8 \\ ( \frac{2(37)}{11} ) - 3y = 8 \\ \frac{74}{11} - 3y = 8 \\ - 3y = 8 - \frac{74}{11} \\ - 3y = \frac{88 - 74}{11} \\ y = - \frac{14}{33}$

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