Question

The solution of the system of linear equations 2(ax - by) + (a + 4b) = 0; 2 (bx + ay) ( b - 4a) = 0

Answer 1

Answer:

2ax – 2by + a + 4b = 0 .... ( 1 ) 2bx + 2ay + b – 4a = 0 ... ( 2 ) Multiplyng ( 1 ) by b and ( 2 ) by a and subtracting , we get 2 ( b2 + a- ) y = 4 ( a² + b2 ) + y = Multiplying ( 1 ) by a and ( 2 ) by b and adding , we get 2 ( a² +62 ) x + a² + b2 = 0 2 ( a² +62 ) x = - ( a ? +62 ) = x Hence x = -1/2 , and y = 2