the solution set of (ax-b) (cx+d)=0 is
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I am not going to show my steps here because that is waaaay too much typing.
A= (bcx+bd) / (cx^2+dx)
B= (acx^2+adx) / (cx+d)
C= (-adx+bd) / (ax^2-bx)
D= (-acx^2+bcx) / (ax-b)
A= (bcx+bd) / (cx^2+dx)
B= (acx^2+adx) / (cx+d)
C= (-adx+bd) / (ax^2-bx)
D= (-acx^2+bcx) / (ax-b)
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