The solution to the equation (125)^2x-3=(1÷25)^x+1
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hello users ....
Given that :
125^(2x-3) = 1/25^(x+1)
solution:-
we know that
1/x = x^(-1)
here,
=> 125^(2x-3) = 1/25^(x+1)
=> 125^(2x-3) = 25^{-(x+1) }
=> 5³^(2x-3) = 5²^ (-x-1)
=> 5^{3(2x-3)} = 5^{2(-x-1)}
by comparing ....
=> 3(2x-3) = 2(-x-1)
=> 6x - 9 = -2x - 2
=> 8 x = 7
=> x = 7/8 Answer
⭐✡ hope it helps ⭐✡
Given that :
125^(2x-3) = 1/25^(x+1)
solution:-
we know that
1/x = x^(-1)
here,
=> 125^(2x-3) = 1/25^(x+1)
=> 125^(2x-3) = 25^{-(x+1) }
=> 5³^(2x-3) = 5²^ (-x-1)
=> 5^{3(2x-3)} = 5^{2(-x-1)}
by comparing ....
=> 3(2x-3) = 2(-x-1)
=> 6x - 9 = -2x - 2
=> 8 x = 7
=> x = 7/8 Answer
⭐✡ hope it helps ⭐✡
Anonymous:
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^^"
thanks
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