The solutions of system of equations ax+by-a+b=0
and bx-ay-a-b=0 are
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The solution of system of equation ax+by- b=0
And bx - ay - a- b=0 are
And bx - ay - a- b=0 are
Answered by
4
The question is incomplete. We are supposed to find the values of x and y.
Here is your answer:
ax + by = a - b (equation 1)
bx - ay = a + b (equation 2)
Now we will multiply both the equations:
a² x + aby = a² - ab
b² x - aby = ab+b²
(a² + b²) x = a² + b²
x = a² + b²/a² + b²
x = 1
Now we will put the value of x in the equation 1. It will look like this:
a(1) + by = a - b
by = a - b - a
by = - b
y = - b/b
y = - 1
So the value of x = 1 and y = -1
If there is any confusion please leave a comment below.
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