Question

The sound from a mosquito is produced when it vibrates its wings at an average rate of 500 vibrations per second. What is the time period of the vibration?

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Answer 1

Frequency = 500 vibrations/second. = (1/500) = 0.002 sec.

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Answer 2

Answer:

0.002

Frequency equals the number of waves that passes a given point per second or the number of oscillations of a vibrating body per second or number of cycles per second.

In this case, a mosquito vibrates its wings at an average rate of 500 vibrations per second. Therefore, the frequency of the sound is 500 Hz.

Time period of the wave is defined as the reciprocal of the frequency of the wave.

That is, T=f1=5001=0.002second.

Hence, time period of the sound produced by the mosquito is 0.002 second.