Question

The specific conductance of 0.1M KCl solution is 1.07 X 10-² ohm-¹ cm-¹. Equivalent conductance will be __________​

Answer 1

Answer: 107 ohm⁻¹cm⁻²equi⁻¹ IS THE ANSWER.

Explanation: Equivalent conductance=1000×specific conductance/Normality

=>equivalent conductance=10³×1.07×10⁻²/0.1 (as for kcl normality=molarity)

                                             =107 ohm⁻¹cm⁻²equi⁻¹

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