Question

The specific conductance of a decimolar solution of KCl is 0.0112 ohm inverse cm inverse .The resistance of a cell containing a solution was found to be 56 ohm .What is the cell constant

Answer 1

Answer:

Cell constant [G*] = 0.672 cm⁻¹

Explanation:

Given data :

Conductivity [κ] = 0.012 Ω⁻¹ cm⁻¹

Resistance [R] = 56 Ω

Cell constant [G*] = ?

By equation, G* = R × κ

[Cell constant = Resistance × Conductivity]

So,

G* = 56 Ω  × 0.012 Ω⁻¹ cm⁻¹

G* = 0.672 cm⁻¹

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