Question

The specific conductance of saturated solution of silver bromide is k.The limiting ionic conductivity of ag+ and br- are x and y respectivelysssolubility of silver bromide ions is

Answer 1

Answer:

Given Specific conductance of AgBr = K S cm

−1

Λ

Ag

+

∘

=x Λ

Br

−

∘

=y

Λ

AgBr

∘

=Λ

Ag

+

∘

+Λ

Br

−

∘

=x+y

Λ

AgBr

∘

=K×

C(molL

−1

)

1000

x+y=

C(molL

−1

)

K×1000

(Solubility) C = (

x+y

K×1000

)mol.L

−1

No. of mol =

molarmass(gmol

- 1

)

mass(g)

molar mass of AgBr = 188 gmol

- 1

So,

C=(

x+y

K×1000

)×188g.L

−1

Explanation:

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Answer 2

Answer:

Ggle

Explanation:

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