Two particles execute shm parallel to x axis about the origin
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Answer:
x
1
=Asinωt
x
2
=Asin(ωt+ϕ)
Given that (A/3=Asinωt)and−A/3=Asin(ωt+ϕ)
Which gives, sin ωt=1/3
sin (ωt+ϕ)=−1/3
sin ω t cos ϕ + cos ω t sin ϕ = -1/3
1/3 cos ϕ +
1−1/9
sin ϕ = -1/3
ϕ = π or cos
−1
(7/9)
Differentiating (i) and (ii) we obtain
v
1
= A ω cosωt and v
2
= A ω cos (ω + ϕ)
If we put ϕ = π, we find v
1
and v
2
are of opposite signs.
ϕ = cos
−1
7/9
Explanation:
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