The specific heat of a gas .075 at constant volume of formula mass 40
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Specificheat of gas at constant
volume=0.075calg^-1C° i.e,0.075cal is absorbed by 1g of it for 1° rise in temperature at constant volume.So,total heat absorbed by 1g mole of the gas is 40(0.075)=3cal.Since,Cp-Cv=R or Cp=5 Cp/Cv=5/3 & hence the gas is monatomic.
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volume=0.075calg^-1C° i.e,0.075cal is absorbed by 1g of it for 1° rise in temperature at constant volume.So,total heat absorbed by 1g mole of the gas is 40(0.075)=3cal.Since,Cp-Cv=R or Cp=5 Cp/Cv=5/3 & hence the gas is monatomic.
Read more on Brainly.in - https://brainly.in/question/978753#readmore
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