Two equal charges of 2×10^-16 C are kept 20cm apart in air. At point midway between them find electric field intensity and force acting on the charge ???
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we know F=q1q2/rsq
so at mid way ris 10 and on applying you will get the ans
so at mid way ris 10 and on applying you will get the ans
sinhsjiya2021p9ubg2:
But as in the given case the two charges are of same sign and magnitude, the electric field will be 0 at the centre.....
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Answer:zero
Explanation: two charges have same magnitude. So they exert equal and opposite force at the middle and cancel each other. So electric field intensity is zero.
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