Question

The specific heat of aluminum is 0.214 cal/g°c. What is the energy, in calories, necessary to raise the temperature of a 55.5 g piece of aluminum from 23.0 to 48.6°C?

Answer 1

Answer:

ΔU=304.05caloriesExplanation:

Data:

C=0.214calg⁻¹°C⁻¹

ΔU=?

mass=55.5g

t₁=23.0°C

t₂=48.6°C

ΔT=48.6-23.0=25.6°C

Formula:

ΔU=nCΔT

Solution:

ΔU=mCΔT

ΔU=(55.5g)(0.214calg⁻¹°C⁻¹)(25.6°C )

ΔU=304.05calories