Question

The specific heat of argon at constant volume is 0.3122kj/kg k. find the specific heat of argon at constant pressure if r = 8.314 kj/k mole k.

Answer 1

Explanation:

Cp- Cv = r

=R÷M

Hope it helps you

Answer 2

520.3

Explanation:

Given that,

r = 8.314 kj/k mole k.

As we know,

$C_{p} - C_{v}$ = r

First, we will find

$C_{vm}$ = $C_{pm}$ - r

$C_{vm}$ = $\frac{3}{2} (8.314)$

∵ $C_{vm}$ = 12.471kJ/kgmol − K

Since,

$C_{v}$ = $C_{vm}$/M

$C_{v}$ = (12.471kJ/kgmol−K)/(39.95 kg/kgmol)

$C_{v}$ = 0.3122kJ/kg−K

So,

$C_{p} - C_{v}$ = r

$C_{p}$ - 0.3122 = r/M

Since Argon has M = 39.95kg/kgmol

$C_{p}$ = 8.314/39.95 * 10^-3 + 0.3122

$C_{P}$ = 0.208110/10^-3 + 0.3122

$C_{P}$ = 0.520310 * 10^-3

$C_{P}$ = 0.520310 * 10^3 * 10^-6

$C_{P}$ = 0.520310 * 10^-3

∵ $C_{P}$ = 520.3 J/kg - K

Learn more: Find the specific heat

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