Question

The specific heat of gas is 0.313 J/g at constant volume. If the molar mass of the gas is 40,
Calculate the atomicity of the gas.
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Answer 1

Answer:

specific heat X atomic mass = 6.4 ( Dulong & petit rule)

0.313 X 40 a = 6.4 on solving a= 0.5 as atomicity can't be in fraction therefore it will be 1

Answer 2

Answer:

The atomicity of the gas is 1.

Explanation:

According to the Dulong & Petit rule, the "specific heat multiplied by atomic mass" is always 6.4.

This law states that the gram-atomic heat capacity of an element is a constant; that is, it is the same for all solid elements, about six calories per gram atom.

Atomic Mass=Molar Mass x Atomicity.

Therefore$0.31 \times(40 \times a)=6.4$ where ‘a’ is the atomicty

$a=\frac{6.4}{(0.313 \times 40)}$

Hence a = 0.5

Since atomicity cannot be written as a decimal, the atomicity becomes 1.