Chemistry, asked by krishb48, 5 months ago

The specific rate of a reaction is 1.5x10-4 lit mole sec-1. If the reaction is commenced with 0.2 mole/lit of the reactant, the initial rate of
the reaction in mole lit 1sec-1 is
O (2) 1.5x104
(b) 3x105
(c) 6x10-6
O (d) 6x10-5​

Answers

Answered by sanjana141421
1

Explanation:

For a general reaction of order n, the units of rate constant is given as (mol/litre)1−nsec−1.

So for our question, the unit of rate constant is (mol/litre)−1sec−1 so 1−n=−1.

So, the value of n=2, so the reaction is of second order.

The rate is given as r=k[A]2. Specific rate of equation is the rate for concentration of 1 mol/litre. 

From this, the value of k is 1.51×10−4.

r=1.51×10−4[A]2.

[A] =  0.2mol/litre. 

Initial rate is 6×10−6.

Hence, option C is correct.

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