The specific rate of a reaction is 1.5x10-4 lit mole sec-1. If the reaction is commenced with 0.2 mole/lit of the reactant, the initial rate of
the reaction in mole lit 1sec-1 is
O (2) 1.5x104
(b) 3x105
(c) 6x10-6
O (d) 6x10-5
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Explanation:
For a general reaction of order n, the units of rate constant is given as (mol/litre)1−nsec−1.
So for our question, the unit of rate constant is (mol/litre)−1sec−1 so 1−n=−1.
So, the value of n=2, so the reaction is of second order.
The rate is given as r=k[A]2. Specific rate of equation is the rate for concentration of 1 mol/litre.
From this, the value of k is 1.51×10−4.
r=1.51×10−4[A]2.
[A] = 0.2mol/litre.
Initial rate is 6×10−6.
Hence, option C is correct.
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