Question

The specific resistance of manganin is 50 × 10–8 ohm × m. The resistance of a cube of

length 50 cm will be


(A) 10–6 ohm (B) 2.5 × 10–6 ohm (C) 10–8 ohm (D) 5 × 10–4 ohm

Answer 1

Answer:

option A

Explanation:

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Answer 2

Answer:

The resistance of the manganin will be equal to 10⁻⁶ ohm.

Explanation:

Given: the specific resistance, $\rho =50*10^{-8}ohm*m=50*10^{-6}ohm*cm$

The length, $l=50cm$

Area of the conductor, $A=(50)^{2}=250cm^{2}$

We know that, $R=\rho(\frac{l}{A} )$

Put the values in above equation:

$R=(50*10^{-6}ohm*cm})(\frac{50cm}{250cm^{2} })$

$R=10^{-6}ohm$

Therefore the resistance of the conductor equals to $10^{-6}$Ω.