the speed of a bicycle reduced from 20m/s to 4 m/s after travelling 80m calculate retardation
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crystal1000:
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v2=u2+2asv2=u2+2as
(0m/s)2=(20m/s)2+2∗a∗10m(0m/s)2=(20m/s)2+2∗a∗10m
0m2/s2=400m2/s2+20m∗a0m2/s2=400m2/s2+20m∗a
20m∗a=−400m2/s220m∗a=−400m2/s2
a=(−400m2/s2)/20ma=(−400m2/s2)/20m
a=−20m/s2a=−20m/s2
Therfore the acceleration of the car is −20m/
(0m/s)2=(20m/s)2+2∗a∗10m(0m/s)2=(20m/s)2+2∗a∗10m
0m2/s2=400m2/s2+20m∗a0m2/s2=400m2/s2+20m∗a
20m∗a=−400m2/s220m∗a=−400m2/s2
a=(−400m2/s2)/20ma=(−400m2/s2)/20m
a=−20m/s2a=−20m/s2
Therfore the acceleration of the car is −20m/
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