Question

the speed of a bus increases from 36kmh-¹to 72 kmh-¹it's acceleration is ​

Answer 1

Answer:

The initial velocity u =36 km/h=10 m/sthe Final velocity v =72 Km/h = 20 m/sThe time period t = 10 s using first equation of motionv – u = atwherev is the final velocityu is the initial velocitya is the accelerationt is the time period putting the value of v,u,t in the equation, we get20 -10 =a ×10a = 1 m/s2

Answer 2

Answer:

the answer is

=a=V-U/t

=but we need to convert km per hour into metre per sec so 36×5/18per sec and 72×5/18

=10-20/t

=acceleration=-1/t

=at=(-1)metre per sec